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Chemistry
Urine normally has a pH of 6 . If a patient eliminates 1.3 litre of urine per day. How many moles of H +ions does he urinate ?
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Q. Urine normally has a $pH$ of $6$ . If a patient eliminates $1.3$ litre of urine per day. How many moles of $H ^{+}$ions does he urinate ?
Equilibrium
A
$1.3 \times 10^{-3}$
0%
B
$1.3 \times 10^{-4}$
0%
C
$1.3 \times 10^{-7}$
0%
D
$1.3 \times 10^{-6}$
100%
Solution:
$pH =6$
$\left[ H ^{+}\right]=10^{-6} M$
Mol $= M \times V$
$=10^{-6} \times 1.3=1.3 \times 10^{-6} mol$