Uncertainty in position of a 0.25 g particle is 10-5. Uncertainty of velocity is (h = 6.6 × 10-34 Js)

Question

Uncertainty in position of a 0.25 g particle is 10-5. Uncertainty of velocity is (h = 6.6 × 10-34 Js) (A) 1.2 × 1034 (B) 2.1 × 10-26 (C) 1.6 × 10-20 (D) 1.7 × 10-9

Tardigrade Admin · Accepted Answer

According to Δ x× m×Δ v=(h/4π); Δ v=(h/Δ x× m×4π) =(6.6×10-34/10-5× 0.25×10-3×3.14×4) = 2.1×10-26 m /s

Q. Uncertainty in position of a $0.25 g$ particle is $1 0^{- 5}$ . Uncertainty of velocity is ( $h = 6.6 \times 1 0^{- 34} J s$ )

$1.2 \times 1 0^{34}$

$2.1 \times 1 0^{- 26}$

$1.6 \times 1 0^{- 20}$

$1.7 \times 1 0^{- 9}$

According to $Δ x \times m \times Δ v = \frac{h}{4 π};$
$Δ v = \frac{h}{Δ x \times m \times 4 π}$
$= \frac{6.6 \times 1 0 ^{- 34}}{1 0 ^{- 5} \times 0.25 \times 1 0 ^{- 3} \times 3.14 \times 4}$
$= 2.1 \times 1 0^{- 26} m / s$

Q. Uncertainty in position of a 0.25g particle is 10−5. Uncertainty of velocity is (h=6.6×10−34Js)

1.2×1034

2.1×10−26

1.6×10−20

1.7×10−9