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Q. Uncertainty in position of a $0.25\, g$ particle is $10^{-5}$. Uncertainty of velocity is ($h = 6.6 \times 10^{-34}\, Js$)

Structure of Atom

Solution:

According to $\Delta x\times m\times\Delta v=\frac{h}{4\pi};$
$\Delta v=\frac{h}{\Delta x\times m\times4\pi} $
$=\frac{6.6\times10^{-34}}{10^{-5}\times 0.25\times10^{-3}\times3.14\times4}$
$= 2.1\times10^{-26} m /s$