Two waves of frequency f and amplitude ' a ' superimpose with each other. The total intensity is directly proportional to

Question

Two waves of frequency f and amplitude ' a ' superimpose with each other. The total intensity is directly proportional to (A) a (B) 2 a (C) 2 a2 (D) 4 a2

Tardigrade Admin · Accepted Answer

When two waves of same frequency f and having same amplitude a superimpose, then resultant amplitude, A=+a=2 a Total intensity I of resultant wave is directly proportional to square of amplitude. i.e., I propto A2 ⇒ I propto(2 a)2 ⇒ I propto 4 a2

Q. Two waves of frequency $f$ and amplitude ' $a$ ' superimpose with each other. The total intensity is directly proportional to

$a$

$2 a$

$2 a^{2}$

$4 a^{2}$

When two waves of same frequency $f$ and having same amplitude $a$ superimpose, then resultant amplitude,
$A = + a = 2 a$
Total intensity $I$ of resultant wave is directly proportional to square of amplitude.
i.e., $I \propto A^{2} \Rightarrow I \propto (2 a)^{2}$
$\Rightarrow I \propto 4 a^{2}$

Q. Two waves of frequency f and amplitude ' a ' superimpose with each other. The total intensity is directly proportional to

a

2a

2a2

4a2

When two waves of same frequency f and having same amplitude a superimpose, then resultant amplitude, A=+a=2a Total intensity I of resultant wave is directly proportional to square of amplitude. i.e., I∝A2⇒I∝(2a)2 ⇒I∝4a2

Q. Two waves of frequency $f$ and amplitude ' $a$ ' superimpose with each other. The total intensity is directly proportional to

$a$

$2 a$

$2 a^{2}$

$4 a^{2}$

When two waves of same frequency $f$ and having same amplitude $a$ superimpose, then resultant amplitude,
$A = + a = 2 a$
Total intensity $I$ of resultant wave is directly proportional to square of amplitude.
i.e., $I \propto A^{2} \Rightarrow I \propto (2 a)^{2}$
$\Rightarrow I \propto 4 a^{2}$