Q. Two tuning forks A and B produce 6 beats per second. If the frequency of A is 512 Hz. The fork B is loaded with wax and they produce 4 beats per second- The frequency of B is:

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Solution:

Number of beats per second Given: frequency of tuning fork A = 512 Hz Hence, frequency of B is Hence, frequency of B is either or After loading the fork 5, the frequency decreases Hence, frequency of fork B become or 508 Therefore, the frequency of fork before loading must be 518 Hz.