1. Tardigrade
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  3. Physics
  4. Two tuning forks A and B produce 6 beats per second. If the frequency of A is 512 Hz. The fork B is loaded with wax and they produce 4 beats per second- The frequency of B is:

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Q. Two tuning forks A and B produce 6 beats per second. If the frequency of A is 512 Hz. The fork B is loaded with wax and they produce 4 beats per second- The frequency of B is:

EAMCETEAMCET 1999

Solution:

Number of beats per second $ {{n}_{1}}-{{n}_{2}}=6 $ Given: frequency of tuning fork A = 512 Hz Hence, frequency of B is $ 512\text{ }\pm \text{ }6 $ Hence, frequency of B is either $ =506Hz $ or $ 518\,Hz $ After loading the fork 5, the frequency decreases Hence, frequency of fork B become $ 512\pm B=4 $ $ B=516 $ or 508 Therefore, the frequency of fork before loading must be 518 Hz.