Question

Two sound waves having a phase difference of $60^{\circ }$ have path difference of

• A. $\frac{\lambda }{6}$
• B. $\frac{\lambda }{3}$
• C. $2\lambda$
• D. $\frac{\lambda }{2}$

Answer 1

Answer: (A)

Phase difference $\theta =60^{\circ }=\frac{\pi }{3}rad$.
Phase difference $(\theta )=\frac{\pi }{3}=\frac{2\pi }{\lambda }\times$ Path difference.
Therefore path difference $=\frac{\pi }{3}\times \frac{\lambda }{2\pi }=\frac{\lambda }{6}$.