Question

Two sound waves having a phase difference of $60^\circ$ have path difference of

• A. $\frac{\lambda}{6}$
• B. $\frac{\lambda}{3}$
• C. $2\lambda$
• D. $\frac{\lambda}{2}$

Answer 1

Answer: (A)

Phase difference $\theta=60^{\circ}=\frac{\pi}{3} \,rad$.
Phase difference $(\theta)=\frac{\pi}{3}=\frac{2 \pi}{\lambda} \times$ Path difference.
Therefore path difference $=\frac{\pi}{3} \times \frac{\lambda}{2 \pi}=\frac{\lambda}{6}$.