Two slits in Young’s double slit experiment have widths in the ratio 81:1. The ratio of the amplitudes of light waves is

Question

Two slits in Young’s double slit experiment have widths in the ratio 81:1. The ratio of the amplitudes of light waves is (A) 3: 1 (B) 3: 2 (C) 9: 1 (D) 6: 1

Tardigrade Admin · Accepted Answer

Width ratio, (β1/β2) = (I1/I2) = (81/1) ∴ Amplitude ratio, (A1/A2) = √(I1/I2) = √(81/1) = 9: 1

Q. Two slits in Young’s double slit experiment have widths in the ratio $81 : 1$ . The ratio of the amplitudes of light waves is

$3 : 1$

$3 : 2$

$9 : 1$

$6 : 1$

Width ratio, $\frac{β _{1}}{β _{2}} = \frac{I _{1}}{I _{2}} = \frac{81}{1}$
$∴$ Amplitude ratio, $\frac{A _{1}}{A _{2}} = \frac{I _{1}}{I _{2}}$
$= \frac{81}{1}$
$= 9 : 1$

Q. Two slits in Young’s double slit experiment have widths in the ratio 81:1. The ratio of the amplitudes of light waves is

3:1

3:2

9:1

6:1