Two resistors R1=(24± 0.5) Ω and R2=(8± 0.3) Ω are joined in series. The equivalent resistance is

Question

Two resistors R1=(24± 0.5) Ω and R2=(8± 0.3) Ω are joined in series. The equivalent resistance is (A) (32± 0.33) Ω  (B) (32± 0.8) Ω  (C) (32± 0.2) Ω  (D) (32± 0.5) Ω

Tardigrade Admin · Accepted Answer

R1=(24±0.5) Ω R2=(8± 0.3) Ω RS=R1+R2 =(32± 0.8) Ω

Q. Two resistors $R_{1} = (24 \pm 0.5) Ω$ and $R_{2} = (8 \pm 0.3) Ω$ are joined in series. The equivalent resistance is

$(32 \pm 0.33) Ω$

$(32 \pm 0.8) Ω$

$(32 \pm 0.2) Ω$

$(32 \pm 0.5) Ω$

$R_{1} = (24 \pm 0.5) Ω$
$R_{2} = (8 \pm 0.3) Ω$
$R_{S} = R_{1} + R_{2}$
$= (32 \pm 0.8) Ω$

Q. Two resistors R1​=(24±0.5)Ω and R2​=(8±0.3)Ω are joined in series. The equivalent resistance is

(32±0.33)Ω

(32±0.8)Ω

(32±0.2)Ω

(32±0.5)Ω