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  4. Two resistors R1=(24± 0.5) Ω and R2=(8± 0.3) Ω are joined in series. The equivalent resistance is

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Q. Two resistors $R_{1}=\left(24\pm 0.5\right)\,\Omega$ and $R_{2}=\left(8\pm 0.3\right)\,\Omega$ are joined in series. The equivalent resistance is

Current Electricity

Solution:

$R_{1}=\left(24\pm0.5\right)\,\Omega$
$R_{2}=\left(8\pm 0.3\right)\,\Omega$
$R_{S}=R_{1}+R_{2}$
$=\left(32\pm 0.8\right)\,\Omega$