Two point electric charges +10-8 C and -10-8 C are placed 0.1 m apart. Find the magnitude of Total Electric field at the center of the line joining the two charges.

Question

Two point electric charges +10-8 C and -10-8 C are placed 0.1 m apart. Find the magnitude of Total Electric field at the center of the line joining the two charges. (A) 3.6 × 104 NC -1 (B) 7.2 × 104 NC -1 (C) zero (D) 12.96 × 104 NC -1

Tardigrade Admin · Accepted Answer

Both charges will give their respective field in same direction ∴ E =(2 kq /(( d )2)2) q =10-8 C d =0.1 m

Q. Two point electric charges $+ 1 0^{- 8} C$ and $- 1 0^{- 8} C$ are placed $0.1 m$ apart. Find the magnitude of Total Electric field at the center of the line joining the two charges.

$3.6 \times 1 0^{4} N C^{- 1}$

$7.2 \times 1 0^{4} N C^{- 1}$

zero

$12.96 \times 1 0^{4} N C^{- 1}$

Both charges will give their respective field in same direction
$∴ E = \frac{2 k q}{( \frac{d}{2} ) ^{2}}$
$q = 1 0^{- 8} C$
$d = 0.1 m$

Q. Two point electric charges +10−8C and −10−8C are placed 0.1m apart. Find the magnitude of Total Electric field at the center of the line joining the two charges.

3.6×104NC−1

7.2×104NC−1