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Q. Two point electric charges $+10^{-8} C$ and $-10^{-8} C$ are placed $0.1 \,m$ apart. Find the magnitude of Total Electric field at the center of the line joining the two charges.

Gujarat CETGujarat CET 2020

Solution:

Both charges will give their respective field in same direction
$\therefore E =\frac{2 kq }{\left(\frac{ d }{2}\right)^{2}}$
$ q =10^{-8} C$
$ d =0.1\, m$