Question

Two pistons of hydraulic press have diameters of $30.0cm$ and $2.5cm$. What is the force (in kg-wt) exerted by larger piston, when $50.0kg-wt$ is placed on the smaller piston?

Answer 1

Answer: 7200

Radius of the pistons: $r=1.25cm$ and $R=15cm$
As $\frac{f}{a}=\frac{F}{A}$
$\therefore F=f\frac{A}{a}=f\frac{\pi R^2}{\pi r^2}$
$=f{\left(\frac{R}{r}\right)}^2=50.0{\left(\frac{15}{1.25}\right)}^2$
$=7200kg-wt$