Question

Two pistons of hydraulic press have diameters of $30.0 \,cm$ and $2.5\, cm$. What is the force (in kg-wt) exerted by larger piston, when $50.0 \,kg-wt$ is placed on the smaller piston?

Answer 1

Radius of the pistons: $r =1.25\,cm$ and $R=15\,cm$
As $\frac{f}{a} = \frac{F}{A}$
$\therefore F=f \frac{A}{a} =f \frac{\pi R^{2}}{\pi r^{2}}$
$=f \left(\frac{R}{r}\right)^{2} =50.0\left(\frac{15}{1.25}\right)^{2} $
$=7200 \, kg-wt$