Two particles of masses 1 kg and 2 kg are located at x1=0, y1=0 and x2=1, y2=0 respectively. The centre of mass of the system is at.

Question

Two particles of masses 1 kg and 2 kg are located at x1=0, y1=0 and x2=1, y2=0 respectively. The centre of mass of the system is at. (A)  x=1; y=2  (B)  x=2; y=1  (C)  x=(1/3); y=(2/3)  (D)  x=(2/3); y=(1/3)

Tardigrade Admin · Accepted Answer

xC M=(m1 x1+m2 x2/m1+m2) ; yC M=(m1 y1+m2 y2/m1+m2) =(1 × 0+2 × 1/3)=(2/3) ; y=(1 × 0+2 × 0/3)=0 [(2/3), 0] Hence, no option is correct.

Q. Two particles of masses $1 k g$ and $2 k g$ are located at $x_{1} = 0, y_{1} = 0$ and $x_{2} = 1, y_{2} = 0$ respectively. The centre of mass of the system is at.

$x = 1; y = 2$

$x = 2; y = 1$

$x = \frac{1}{3}; y = \frac{2}{3}$

$x = \frac{2}{3}; y = \frac{1}{3}$

$x_{CM} = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}};$
$y_{CM} = \frac{m _{1} y _{1} + m _{2} y _{2}}{m _{1} + m _{2}}$
$= \frac{1 \times 0 + 2 \times 1}{3} = \frac{2}{3}; y = \frac{1 \times 0 + 2 \times 0}{3} = 0$
$[\frac{2}{3}, 0]$
Hence, no option is correct.

Q. Two particles of masses 1kg and 2kg are located at x1​=0,y1​=0 and x2​=1,y2​=0 respectively. The centre of mass of the system is at.

x=1;y=2

x=2;y=1

x=31​;y=32​

x=32​;y=31​