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Q. Two particles of masses $1\, kg$ and $2\, kg$ are located at $x_{1}=0, y_{1}=0$ and $x_{2}=1,\, y_{2}=0$ respectively. The centre of mass of the system is at.

J & K CETJ & K CET 2010System of Particles and Rotational Motion

Solution:

$x_{C M}=\frac{m_{1} x_{1}+m_{2} x_{2}}{m_{1}+m_{2}} ;$
$y_{C M}=\frac{m_{1} y_{1}+m_{2} y_{2}}{m_{1}+m_{2}}$
$=\frac{1 \times 0+2 \times 1}{3}=\frac{2}{3} ; y=\frac{1 \times 0+2 \times 0}{3}=0$
${\left[\frac{2}{3}, 0\right]}$
Hence, no option is correct.