Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5 kg particle is nearly at a distance of :

Question

Two particles of mass 5 kg and 10 kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5 kg particle is nearly at a distance of : (A) 33 cm (B) 50 cm (C) 67 cm (D) 80 cm

Tardigrade Admin · Accepted Answer

Let position of centre of mass be (xc.m, 0) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/b87d1609b47056cf6f291236f54049bc-.png" /> xcm=(m1x1+m2x2/m1+m2) =(5 × 0+100 × 10/5+10) =(200/2) =66.66 cm xcm=67 cm

Q. Two particles of mass $5 k g$ and $10 k g$ respectively are attached to the two ends of a rigid rod of length 1m with negligible mass.
The centre of mass of the system from the $5 k g$ particle is nearly at a distance of :

33 cm

50 cm

67 cm

80 cm

Let position of centre of mass be $(x_{c . m}, 0)$

$x_{c m} = \frac{m _{1} x _{1} + m _{2} x _{2}}{m _{1} + m _{2}}$
$= \frac{5 \times 0 + 100 \times 10}{5 + 10}$
$= \frac{200}{2}$
$= 66.66 c m$
$x_{c m} = 67 c m$

Q. Two particles of mass 5kg and 10kg respectively are attached to the two ends of a rigid rod of length 1m with negligible mass. The centre of mass of the system from the 5kg particle is nearly at a distance of :