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Q. Two particles of mass $5\,kg$ and $10\,kg$ respectively are attached to the two ends of a rigid rod of length 1m with negligible mass.
The centre of mass of the system from the $5\,kg$ particle is nearly at a distance of :

NEETNEET 2020Work, Energy and Power

Solution:

Let position of centre of mass be ${(x_{c.m}, 0)}$
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$x_{cm}=\frac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}$
$=\frac{5 \times 0+100 \times 10}{5+10}$
$=\frac{200}{2}$
$=66.66\,cm$
$x_{cm}=67\,cm$