Two particles A, B are moving on two concentric circles of radii R1 and R2 with equal angular speed ω . At t=0, their positions and direction of motion are shown in the figure: The relative velocity overset arrow VA- overset arrow VB at t=(π /2 ω ) is given by:

Question

Two particles A, B are moving on two concentric circles of radii R1 and R2 with equal angular speed ω . At t=0, their positions and direction of motion are shown in the figure: <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-iztbeeffxuwwfpsq.jpg" /> The relative velocity overset arrow VA- overset arrow VB at t=(π /2 ω ) is given by: (A) -ω (R1 + R2) hati (B) ω (R1 + R2) hati (C) ω (R1 - R2) hati (D) ω (R2 - R1) hati

Tardigrade Admin · Accepted Answer

t=(π /2 ω ) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-iztbeeffxuwwcixw.jpg" /> ( overset arrow V)A=ω R1(- hati) ( overset arrow V)B=ω R2(- hati) overset arrow VA- overset arrow VB=ω (R2 - R1) hati

Q. Two particles $A, B$ are moving on two concentric circles of radii $R_{1}$ and $R_{2}$ with equal angular speed $ω .$ At $t = 0,$ their positions and direction of motion are shown in the figure:

The relative velocity $V_{A} \to - V_{B} \to$ at $t = \frac{π}{2 ω}$ is given by:

$- ω (R_{1} + R_{2}) \hat{i}$

$ω (R_{1} + R_{2}) \hat{i}$

$ω (R_{1} - R_{2}) \hat{i}$

$ω (R_{2} - R_{1}) \hat{i}$

$t = \frac{π}{2 ω}$

$(V \to)_{A} = ω R_{1} (- \hat{i})$
$(V \to)_{B} = ω R_{2} (- \hat{i})$
$V_{A} \to - V_{B} \to = ω (R_{2} - R_{1}) \hat{i}$

Q. Two particles A,B are moving on two concentric circles of radii R1​ and R2​ with equal angular speed ω. At t=0, their positions and direction of motion are shown in the figure: The relative velocity VA​→​−VB​→​ at t=2ωπ​ is given by:

−ω(R1​+R2​)i^

ω(R1​+R2​)i^

ω(R1​−R2​)i^

ω(R2​−R1​)i^