Two parallel unlike forces of magnitudes 15 N and 10 N are acting at points A and B respectively. If C is the point of action of resultant, then AB/BC is

Question

Two parallel unlike forces of magnitudes 15 N and 10 N are acting at points A and B respectively. If C is the point of action of resultant, then AB/BC is (A) 2/1 (B) 1/2 (C) 2/3 (D) 3/2

Tardigrade Admin · Accepted Answer

∴ A C=((A B)/15-10) × 15 <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/747b81843e255d65fdf3d6cbb78b0a55-.png" /> ⇒ (A B+B C)=3 A B ⇒ 2 A B=B C ⇒ (A B/B C)=(1/2)

Q. Two parallel unlike forces of magnitudes $15 N$ and $10 N$ are acting at points $A$ and $B$ respectively. If $C$ is the point of action of resultant, then $A B / BC$ is

2/1

1/2

2/3

3/2

$∴ A C = \frac{( A B )}{15 - 10} \times 15$

$\Rightarrow (A B + BC) = 3 A B$
$\Rightarrow 2 A B = BC \Rightarrow \frac{A B}{BC} = \frac{1}{2}$

Q. Two parallel unlike forces of magnitudes 15N and 10N are acting at points A and B respectively. If C is the point of action of resultant, then AB/BC is

2/1

1/2

2/3

3/2

∴AC=15−10(AB)​×15 ⇒(AB+BC)=3AB ⇒2AB=BC⇒BCAB​=21​

Q. Two parallel unlike forces of magnitudes $15 N$ and $10 N$ are acting at points $A$ and $B$ respectively. If $C$ is the point of action of resultant, then $A B / BC$ is

$∴ A C = \frac{( A B )}{15 - 10} \times 15$

$\Rightarrow (A B + BC) = 3 A B$
$\Rightarrow 2 A B = BC \Rightarrow \frac{A B}{BC} = \frac{1}{2}$