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  4. Two parallel unlike forces of magnitudes 15 N and 10 N are acting at points A and B respectively. If C is the point of action of resultant, then AB/BC is

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Q. Two parallel unlike forces of magnitudes $15\, N$ and $10 \,N$ are acting at points $A$ and $B$ respectively. If $C$ is the point of action of resultant, then $AB/BC$ is

UPSEEUPSEE 2011

Solution:

$\therefore A C=\frac{(A B)}{15-10} \times 15$
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$\Rightarrow (A B+B C)=3 A B$
$\Rightarrow 2 A B=B C \Rightarrow \frac{A B}{B C}=\frac{1}{2}$