Two moles of N 2 gas in a 50 L vessel at STP shows

Question

Two moles of N 2 gas in a 50 L vessel at STP shows (A) positive deviation (B) negative deviation (C) ideal gas behaviour (D) first positive then negative deviation.

Tardigrade Admin · Accepted Answer

Z=(P V/n R T) at STP , P=1 atm , T=273 K Given, V=50 L , n=2 mol , R=0.0821 L atm K -1 mol -1 Z=(1 × 50/2 × 0.0821 × 273)=1.1 Since Z>1, the gas shows positive deviation from ideal behaviour.

Q. Two moles of $N_{2}$ gas in a $50 L$ vessel at $STP$ shows

positive deviation

negative deviation

ideal gas behaviour

first positive then negative deviation.

$Z = \frac{P V}{n RT}$

at $STP, P = 1 a t m, T = 273 K$

Given, $V = 50 L, n = 2 m o l, R = 0.0821 L$ atm $K^{- 1} m o l^{- 1}$

$Z = \frac{1 \times 50}{2 \times 0.0821 \times 273} = 1.1$

Since $Z > 1,$ the gas shows positive deviation from ideal behaviour.

Q. Two moles of N2​ gas in a 50L vessel at STP shows