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Chemistry
Two moles of N 2 gas in a 50 L vessel at STP shows
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Q. Two moles of $N _{2}$ gas in a $50\, L$ vessel at $STP$ shows
States of Matter
A
positive deviation
30%
B
negative deviation
18%
C
ideal gas behaviour
39%
D
first positive then negative deviation.
13%
Solution:
$Z=\frac{P V}{n R T}$
at $STP , P=1 \,atm , T=273 \,K$
Given, $ V=50 L , n=2 \,mol , R=0.0821 \,L$ atm $K ^{-1} mol ^{-1}$
$Z=\frac{1 \times 50}{2 \times 0.0821 \times 273}=1.1$
Since $Z>1,$ the gas shows positive deviation from ideal behaviour.