Two masses of 10 kg and 5 kg are suspended from a rigid support as shown in the figure. The system is pulled down with a force of 150 N attached to the lower mass. The string attached to the support breaks and the system accelerates downwards. In case the force continues to act, the tension acting between the two masses is

Question

Two masses of 10 kg and 5 kg are suspended from a rigid support as shown in the figure. The system is pulled down with a force of 150 N attached to the lower mass. The string attached to the support breaks and the system accelerates downwards. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-s8oq8npmgs0v.png" /> In case the force continues to act, the tension acting between the two masses is (A) 300N (B) 200N (C) 100N (D) Zero

Tardigrade Admin · Accepted Answer

After string breaks, the acceleration of block will be texta=(150 + 15 × 10/15)=20 text m s- 2 <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-s8oq8npmmkmu.png" /> 150+50- textT=5× 20 textT=100 textN

$300 N$

$200 N$

$100 N$

Zero

After string breaks, the acceleration of block will be
$a = \frac{150 + 15 \times 10}{15} = 20 m s^{- 2}$

$150 + 50 - T = 5 \times 20$
$T = 100 N$

300N

200N

100N

Zero

After string breaks, the acceleration of block will be a=15150+15×10​=20 m s−2 150+50−T=5×20 T=100N

$300 N$

$200 N$

$100 N$

After string breaks, the acceleration of block will be
$a = \frac{150 + 15 \times 10}{15} = 20 m s^{- 2}$

$150 + 50 - T = 5 \times 20$
$T = 100 N$