Two masses m1 and m2 (m1 m2) are connected by a massless flexible and inextensible string passed over a massless and frictionless pulley. The acceleration of the centre of mass is

Question

Two masses m1 and m2 (m1 > m2) are connected by a massless flexible and inextensible string passed over a massless and frictionless pulley. The acceleration of the centre of mass is (A) ((m1 - m2/m1 + m2))2g (B) (m1 - m2/m1 + m2)g (C) (m1 + m2/m1 - m2)g (D) Zero

Tardigrade Admin · Accepted Answer

Acceleration of each mass =a=((m1 - m2/m1 + m2))g Now acceleration of centre of mass of the system Ac m=(m1 a1+m1 a2/m1+m2) As both masses move with same acceleration but in opposite direction so a1=-a2=a (let) <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-l7cm4yrdygdmbisb.jpg" /> ∴ Ac m=(m1 a - m2 a/m1 + m2) =((m1 - m2/m1 + m2))× ((m1 - m2/m1 + m2))× g =((m1 - m2/m1 + m2))2× g

Q. Two masses $m_{1}$ and $m_{2} (m_{1} > m_{2})$ are connected by a massless flexible and inextensible string passed over a massless and frictionless pulley. The acceleration of the centre of mass is

$(\frac{m _{1} - m _{2}}{m _{1} + m _{2}})^{2} g$

$\frac{m _{1} - m _{2}}{m _{1} + m _{2}} g$

$\frac{m _{1} + m _{2}}{m _{1} - m _{2}} g$

Zero

Q. Two masses m1​ and m2​(m1​>m2​) are connected by a massless flexible and inextensible string passed over a massless and frictionless pulley. The acceleration of the centre of mass is

(m1​+m2​m1​−m2​​)2g

m1​+m2​m1​−m2​​g

m1​−m2​m1​+m2​​g

Zero

Q. Two masses $m_{1}$ and $m_{2} (m_{1} > m_{2})$ are connected by a massless flexible and inextensible string passed over a massless and frictionless pulley. The acceleration of the centre of mass is

$(\frac{m _{1} - m _{2}}{m _{1} + m _{2}})^{2} g$

$\frac{m _{1} - m _{2}}{m _{1} + m _{2}} g$

$\frac{m _{1} + m _{2}}{m _{1} - m _{2}} g$