Two long parallel copper wires carry currents of 5A each in opposite directions. If the wires are separated by a distance of 0.5m, then the force between the two wires is

Question

Two long parallel copper wires carry currents of 5A each in opposite directions. If the wires are separated by a distance of 0.5m, then the force between the two wires is (A) 10- 5N, attractive (B) 10- 5N repulsive (C) 2× 10- 5N, attractive (D) 2× 10- 5N, repulsive

Tardigrade Admin · Accepted Answer

F=10- 7(2 i1 i2/g)=10- 7× (2 × 5 × 5/0 . 5)=10- 5N (repulsive)

Q. Two long parallel copper wires carry currents of $5 A$ each in opposite directions. If the wires are separated by a distance of $0.5 m,$ then the force between the two wires is

$1 0^{- 5} N,$ attractive

$1 0^{- 5} N$ repulsive

$2 \times 1 0^{- 5} N,$ attractive

$2 \times 1 0^{- 5} N,$ repulsive

$F = 1 0^{- 7} \frac{2 i _{1} i _{2}}{g} = 1 0^{- 7} \times \frac{2 \times 5 \times 5}{0.5} = 1 0^{- 5} N$ (repulsive)

Q. Two long parallel copper wires carry currents of 5A each in opposite directions. If the wires are separated by a distance of 0.5m, then the force between the two wires is

10−5N, attractive

10−5N repulsive

2×10−5N, attractive

2×10−5N, repulsive