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Q. Two long parallel copper wires carry currents of $5A$ each in opposite directions. If the wires are separated by a distance of $0.5m,$ then the force between the two wires is

NTA AbhyasNTA Abhyas 2020

Solution:

$F=10^{- 7}\frac{2 i_{1} i_{2}}{g}=10^{- 7}\times \frac{2 \times 5 \times 5}{0 . 5}=10^{- 5}N$ (repulsive)