Two ions A+ and B- have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound AB. The co-ordination no. of A is

Question

Two ions A+ and B- have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound AB. The co-ordination no. of A is (A) 4 (B) 8 (C) 6 (D) 3

Tardigrade Admin · Accepted Answer

Radius ratio= (r+/r-) = (104 pm/200 pm) = 0.52 As it lies in the range 0.414 - 0.732, the coordination number will be 6

Q. Two ions $A^{+}$ and $B^{-}$ have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound AB. The co-ordination no. of A is

4

8

6

3

Radius ratio= $\frac{r _{+}}{r _{-}} = \frac{104 p m}{200 p m} = 0.52$ As it lies in the range 0.414 - 0.732, the coordination number will be 6

Q. Two ions A+ and B− have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound AB. The co-ordination no. of A is

4

8

6

3

Radius ratio= r−​r+​​=200pm104pm​=0.52 As it lies in the range 0.414 - 0.732, the coordination number will be 6

Q. Two ions $A^{+}$ and $B^{-}$ have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound AB. The co-ordination no. of A is

Radius ratio= $\frac{r _{+}}{r _{-}} = \frac{104 p m}{200 p m} = 0.52$ As it lies in the range 0.414 - 0.732, the coordination number will be 6