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Q. Two ions $A^+$ and $B^-$ have radii 104 and 200 pm respectively, in a cubic close packed crystal of compound AB. The co-ordination no. of A is

COMEDKCOMEDK 2012The Solid State

Solution:

Radius ratio= $\frac{r_+}{r_-} = \frac{104 \, pm}{200 \, pm} = 0.52$ As it lies in the range 0.414 - 0.732, the coordination number will be 6