Question

Two dice are thrown simultaneously. The probability of obtaining a total score of seven is $\frac{1}{m}$. The value of ' $m$ ' is

• A. 3
• B. 2
• C. 6
• D. 9

Answer 1

Answer: (C)

When two dice are thrown then there are $6\times 6$ exhaustive cases
$\therefore n=36$. Let $A$ denote the event "total score of $7$ "
when $2$ dice are thrown then
$A=\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}$
Thus there are $6$ favourable cases.
$\therefore m=6$
By definition $P(A)=\frac{m}{n}$
$\therefore P(A)=\frac{6}{36}=\frac{1}{6}$.