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Q.
Two dice are thrown simultaneously. The probability of obtaining a total score of seven is $\frac{1}{m}$. The value of ' $m$ ' is
Probability
Solution:
When two dice are thrown then there are $6 \times 6$ exhaustive cases
$\therefore n =36$. Let $A$ denote the event "total score of $7$ "
when $2$ dice are thrown then
$A =\{(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)\}$
Thus there are $6$ favourable cases.
$\therefore m =6$
By definition $P ( A )=\frac{ m }{ n }$
$ \therefore P ( A )=\frac{6}{36}=\frac{1}{6}$.