Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are

Question

Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are (A) 5I and I (B) 5I and 3 I (C) 9I and I (D) 9I and 3 I

Tardigrade Admin · Accepted Answer

Imax=(√I1+√I2)2=(√4I+√ I)2=9I Imin=(√I1-√I2)2=(√4I-√ I)2=I ∴ Correct option is (c ).

Q. Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are

5I and I

5I and 3 I

9I and I

9I and 3 I

$I_{ma x} = (I_{1} + I_{2})^{2} = (4 I + I)^{2} = 9 I$
$I_{min} = (I_{1} - I_{2})^{2} = (4 I - I)^{2} = I$
$∴$ Correct option is (c ).

Q. Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible intensities in the resulting beam are

5I and I

5I and 3 I

9I and I

9I and 3 I

Imax​=(I1​​+I2​​)2=(4I​+I​)2=9I Imin​=(I1​​−I2​​)2=(4I​−I​)2=I ∴ Correct option is (c ).

$I_{ma x} = (I_{1} + I_{2})^{2} = (4 I + I)^{2} = 9 I$
$I_{min} = (I_{1} - I_{2})^{2} = (4 I - I)^{2} = I$
$∴$ Correct option is (c ).