Two charges of 1 nC and 4 nC are placed (1/2) m apart. The ratio of the Coulomb forces experienced by the two charges is

Question

Two charges of 1 nC and 4 nC are placed (1/2) m apart. The ratio of the Coulomb forces experienced by the two charges is (A)  1: 1 (B) 1: 9 (C) 9: 1 (D) 1: 81

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/743a81add67b4b832269fc03efc5d2ac-.png" /> ddotF12=- vecF12 (Newton's III rd law ) ⇒ (F12/F21)=1: 1

Q. Two charges of $1 n C$ and $4 n C$ are placed $\frac{1}{2} m$ apart. The ratio of the Coulomb forces experienced by the two charges is

$1 : 1$

$1 : 9$

$9 : 1$

$1 : 81$

$\ddot{F}_{12} = - F_{12}$ (Newton's $II I^{r d}$ law $) \Rightarrow \frac{F _{12}}{F _{21}} = 1 : 1$

Q. Two charges of 1nC and 4nC are placed 21​m apart. The ratio of the Coulomb forces experienced by the two charges is

1:1

1:9

9:1

1:81