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  4. Two charges of 1 nC and 4 nC are placed (1/2) m apart. The ratio of the Coulomb forces experienced by the two charges is

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Q. Two charges of $1 \,nC$ and $4\, nC$ are placed $\frac{1}{2} m$ apart. The ratio of the Coulomb forces experienced by the two charges is

Electric Charges and Fields

Solution:

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$\ddot{F}_{12}=-\vec{F}_{12}$ (Newton's $III ^{ {rd }}$ law $) \Rightarrow \frac{F_{12}}{F_{21}}=1: 1$