Two capacitors of capacity C1 and C2 are connected in series and potential difference V is applied across it. Then the potential difference across C1 will be

Question

Two capacitors of capacity C1 and C2 are connected in series and potential difference V is applied across it. Then the potential difference across C1 will be (A) V (C2/C1) (B) V (C1+C2/C1) (C) V (C2/C1+C2) (D) V (C1/C1+C2)

Tardigrade Admin · Accepted Answer

Charge flowing =(C1 C2/C1+C2) V Potential difference across C1=(C1 C2 V/C1+C2) × (1/C1) =(C2 V/C1+C2)

Q. Two capacitors of capacity $C_{1}$ and $C_{2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_{1}$ will be

$V \frac{C _{2}}{C _{1}}$

$V \frac{C _{1} + C _{2}}{C _{1}}$

$V \frac{C _{2}}{C _{1} + C _{2}}$

$V \frac{C _{1}}{C _{1} + C _{2}}$

Charge flowing $= \frac{C _{1} C _{2}}{C _{1} + C _{2}} V$
Potential difference across
$C_{1} = \frac{C _{1} C _{2} V}{C _{1} + C _{2}} \times \frac{1}{C _{1}}$
$= \frac{C _{2} V}{C _{1} + C _{2}}$

Q. Two capacitors of capacity C1​ and C2​ are connected in series and potential difference V is applied across it. Then the potential difference across C1​ will be

VC1​C2​​

VC1​C1​+C2​​

VC1​+C2​C2​​

VC1​+C2​C1​​