Question

Two capacitors of capacity $C_{1}$ and $C_{2}$ are connected in series and potential difference $V$ is applied across it. Then the potential difference across $C_{1}$ will be

• A. $V \frac{C_{2}}{C_{1}}$
• B. $V \frac{C_{1}+C_{2}}{C_{1}}$
• C. $V \frac{C_{2}}{C_{1}+C_{2}}$
• D. $V \frac{C_{1}}{C_{1}+C_{2}}$

Answer 1

Answer: (C)

Charge flowing $=\frac{C_{1} C_{2}}{C_{1}+C_{2}} V$
Potential difference across
$C_{1}=\frac{C_{1} C_{2} V}{C_{1}+C_{2}} \times \frac{1}{C_{1}}$
$=\frac{C_{2} V}{C_{1}+C_{2}}$