Question

Two capacitors $A$ and $B$ are connected in series with a battery as shown in figure. When the switch $S$ is closed and the two capacitors get charged fully, then

• A. the potential difference across the plates of $A$ is $4V$ and across the plates of $B$ is $6V$
• B. the potential difference across the plates of $A$ is $6V$ and across the plates of $B$ is $4V$.
• C. the ratio of electrical energies stored in $A$ and $B$ is $2:3$.
• D. the ratio of charges on $A$ and $B$ is $3:2$.

Answer 1

Answer: (B)

In series combination, charge on each capacitor is same. Potential difference divides in the inverse ratio of capacities.
$\therefore$ Potential difference across
$A=\frac{10\times 3}{2+3}=6V$
Potential difference across
$B=\frac{10\times 2}{2+3}=4V$