Question

Two capacitors $A$ and $B$ are connected in series with a battery as shown in figure. When the switch $S$ is closed and the two capacitors get charged fully, then

• A. the potential difference across the plates of $A$ is $4 \,V$ and across the plates of $B$ is $6 \,V$
• B. the potential difference across the plates of $A$ is $6 \,V$ and across the plates of $B$ is $4\, V$.
• C. the ratio of electrical energies stored in $A$ and $B$ is $2: 3$.
• D. the ratio of charges on $A$ and $B$ is $3: 2$.

Answer 1

Answer: (B)

In series combination, charge on each capacitor is same. Potential difference divides in the inverse ratio of capacities.
$\therefore $ Potential difference across
$A=\frac{10 \times 3}{2+3}=6\, V$
Potential difference across
$B=\frac{10 \times 2}{2+3}=4\, V$