Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is:

Question

Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is: <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bb97d67a3eca39a55681bdf768f18d44-.png" /> (A) (11/6) π (B) π (C) (5/3) π (D) (3/5) π

Tardigrade Admin · Accepted Answer

From the given figure if we draw the phase diagram on circular motion representation it looks like

v from figure phase difference between

1&2

is given as

cos θ = \frac{A /2}{A} = \frac{1}{2}

\Rightarrow θ = \frac{π}{3} or 2 π - \frac{π}{3} = \frac{5 π}{3}

Q. Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is:

$\frac{11}{6} π$

$π$

$\frac{5}{3} π$

$\frac{3}{5} π$

From the given figure if we draw the phase diagram on circular motion representation it looks like

v from figure phase difference between $1&2$ is given as
$cos θ = \frac{A /2}{A} = \frac{1}{2}$
$\Rightarrow θ = \frac{π}{3} or 2 π - \frac{π}{3} = \frac{5 π}{3}$

Q. Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is:

611​π

π

35​π

53​π

From the given figure if we draw the phase diagram on circular motion representation it looks like v from figure phase difference between 1&2 is given as cosθ=AA/2​=21​ ⇒θ=3π​ or 2π−3π​=35π​

$\frac{11}{6} π$

$π$

$\frac{5}{3} π$

$\frac{3}{5} π$

From the given figure if we draw the phase diagram on circular motion representation it looks like

v from figure phase difference between $1&2$ is given as
$cos θ = \frac{A /2}{A} = \frac{1}{2}$
$\Rightarrow θ = \frac{π}{3} or 2 π - \frac{π}{3} = \frac{5 π}{3}$