Question

Two bodies performing SHM have same amplitude and frequency. Their phases at a certain instant are as shown in the figure. The phase difference between them is:

• A. $\frac{11}{6} \pi$
• B. $\pi$
• C. $\frac{5}{3} \pi$
• D. $\frac{3}{5} \pi$

Answer 1

Answer: (C)

From the given figure if we draw the phase diagram on circular motion representation it looks like

v from figure phase difference between $1 \& 2$ is given as
$\cos \theta=\frac{A / 2}{A}=\frac{1}{2} $
$\Rightarrow \theta=\frac{\pi}{3} \text { or } 2 \pi-\frac{\pi}{3}=\frac{5 \pi}{3}$