Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F = 600 N is applied to 20 kg as shown Then the tension in the string is

Question

Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F = 600 N is applied to 20 kg as shown <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/ad3d5a8750fbb02f39cb9b3b0e8518f8-.png" /> Then the tension in the string is (A) 100 N (B) 200 N (C) 300 N (D) 400 N

Tardigrade Admin · Accepted Answer

For the 20 kg mass, 600-T=20 a a=(600 N /(20 kg +10 kg ))=20 ms -2 ⇒ T=600-20(a)=600-(20)(20)=200 N

Q. Two bodies of masses $10 k g$ and $20 k g$ respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force $F = 600 N$ is applied to $20 k g$ as shown

Then the tension in the string is

100 N

200 N

300 N

400 N

For the $20 k g$ mass,
$600 - T = 20 a$
$a = \frac{600 N}{( 20 k g + 10 k g )} = 20 m s^{- 2}$
$\Rightarrow T = 600 - 20 (a) = 600 - (20) (20) = 200 N$

Q. Two bodies of masses 10kg and 20kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F=600N is applied to 20kg as shown Then the tension in the string is