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  4. Two bodies of masses 10 kg and 20 kg respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force F = 600 N is applied to 20 kg as shown <img class=img-fluid question-image alt=image src=https://cdn.tardigrade.in/img/question/physics/ad3d5a8750fbb02f39cb9b3b0e8518f8-.png /> Then the tension in the string is

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Q. Two bodies of masses $10\, kg$ and $20\, kg$ respectively kept on a smooth, horizontal surface are tied to the ends of a light string. A horizontal force $F = 600\, N$ is applied to $20 \,kg$ as shown
image
Then the tension in the string is

Laws of Motion

Solution:

For the $20\, kg$ mass,
$600-T=20 a$
$a=\frac{600 N }{(20 kg +10 kg )}=20 ms ^{-2}$
$\Rightarrow T=600-20(a)=600-(20)(20)=200 N$