Two bodies of different masses ma and mb are allowed to fall from different heights a and b. The ratio of time taken by the two to cover these distances are

Question

Two bodies of different masses ma and mb are allowed to fall from different heights a and b. The ratio of time taken by the two to cover these distances are (A) a: b (B) b: a (C) √ a:√ b (D) a2 :b2.

Tardigrade Admin · Accepted Answer

Using, S = ut + (1/2) gt2 , we get t propto √s ∴ t2:t2::√a:√b

Q. Two bodies of different masses $m_{a} an d m_{b}$ are allowed to fall from different heights $a$ and $b$ . The ratio of time taken by the two to cover these distances are

a : b

b : a

$a : b$

$a^{2} : b^{2}$ .

Using, S = $u t + \frac{1}{2} g t^{2}$ ,
we get $t \propto s$
$∴ t_{2} : t_{2} :: a : b$

Q. Two bodies of different masses ma​andmb​ are allowed to fall from different heights a and b. The ratio of time taken by the two to cover these distances are

a : b

b : a

a​:b​

a2:b2.

Using, S = ut+21​gt2, we get t∝s​ ∴t2​:t2​::a​:b​

Q. Two bodies of different masses $m_{a} an d m_{b}$ are allowed to fall from different heights $a$ and $b$ . The ratio of time taken by the two to cover these distances are

$a : b$

$a^{2} : b^{2}$ .

Using, S = $u t + \frac{1}{2} g t^{2}$ ,
we get $t \propto s$
$∴ t_{2} : t_{2} :: a : b$