Two blocks of masses 0.2 kg and 0.5 kg which are placed 22 m apart on a rough horizontal surface (μ=0.5) are acted upon by two forces of magnitude 3 N each as shown in the figure at time t=0. Then the time t (in s) at which they collide with each other is

Question

Two blocks of masses 0.2 kg and 0.5 kg which are placed 22 m apart on a rough horizontal surface (μ=0.5) are acted upon by two forces of magnitude 3 N each as shown in the figure at time t=0. Then the time t (in s) at which they collide with each other is (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

a1=(F-f1/m1)=(F-μ m1 g/m1)=10 m / s 2 ; a2=(-F+μ m2 g/m2)=-1 m / s 2 ∴ S=(1/2) a text rel ⋅ t2 ⇒ 22=(1/2)[10-(-1)] t2 ⇒ t=2 s

Q. Two blocks of masses $0.2 k g$ and $0.5 k g$ which are placed $22 m$ apart on a rough horizontal surface $(μ = 0.5)$ are acted upon by two forces of magnitude $3 N$ each as shown in the figure at time $t = 0$ . Then the time $t$ (in $s$ ) at which they collide with each other is

$a_{1} = \frac{F - f _{1}}{m _{1}} = \frac{F - μ m _{1} g}{m _{1}} = 10 m / s^{2};$
$a_{2} = \frac{- F + μ m _{2} g}{m _{2}} = - 1 m / s^{2}$
$∴ S = \frac{1}{2} a_{rel} \cdot t^{2}$
$\Rightarrow 22 = \frac{1}{2} [10 - (- 1)] t^{2}$
$\Rightarrow t = 2 s$

Q. Two blocks of masses 0.2kg and 0.5kg which are placed 22m apart on a rough horizontal surface (μ=0.5) are acted upon by two forces of magnitude 3N each as shown in the figure at time t=0. Then the time t (in s) at which they collide with each other is

a1​=m1​F−f1​​=m1​F−μm1​g​=10m/s2; a2​=m2​−F+μm2​g​=−1m/s2 ∴S=21​a rel ​⋅t2 ⇒22=21​[10−(−1)]t2 ⇒t=2s

Q. Two blocks of masses $0.2 k g$ and $0.5 k g$ which are placed $22 m$ apart on a rough horizontal surface $(μ = 0.5)$ are acted upon by two forces of magnitude $3 N$ each as shown in the figure at time $t = 0$ . Then the time $t$ (in $s$ ) at which they collide with each other is

$a_{1} = \frac{F - f _{1}}{m _{1}} = \frac{F - μ m _{1} g}{m _{1}} = 10 m / s^{2};$
$a_{2} = \frac{- F + μ m _{2} g}{m _{2}} = - 1 m / s^{2}$
$∴ S = \frac{1}{2} a_{rel} \cdot t^{2}$
$\Rightarrow 22 = \frac{1}{2} [10 - (- 1)] t^{2}$
$\Rightarrow t = 2 s$