Two block of mass 3 kg and m kg connected to each other with the help of string which passes over a frictionless pulley. If the acceleration of system is (g/4)

Question

Two block of mass 3 kg and m kg connected to each other with the help of string which passes over a frictionless pulley. If the acceleration of system is (g/4) (A) 1.5 kg (B) 1.8 kg (C) 0.5 kg (D) 1 kg

Tardigrade Admin · Accepted Answer

a=((m2-m1)/(m1+m2)) g (g/4)=((3-m/3+m)) g (1/4)=(3-m/3+m) ⇒ 3+m=12-4 m 5 m=9 ⇒ m=9 / 5=1.8 kg

Q. Two block of mass $3 k g$ and $mk g$ connected to each other with the help of string which passes over a frictionless pulley. If the acceleration of system is $\frac{g}{4}$

$1.5 k g$

$1.8 k g$

$0.5 k g$

$1 k g$

$a = \frac{( m _{2} - m _{1} )}{( m _{1} + m _{2} )} g$
$\frac{g}{4} = (\frac{3 - m}{3 + m}) g$
$\frac{1}{4} = \frac{3 - m}{3 + m}$
$\Rightarrow 3 + m = 12 - 4 m$
$5 m = 9$
$\Rightarrow m = 9/5 = 1.8 k g$

Q. Two block of mass 3kg and mkg connected to each other with the help of string which passes over a frictionless pulley. If the acceleration of system is 4g​

1.5kg

1.8kg

0.5kg

1kg