Two billiard balls each of mass 50 g moving in opposite directions with a speed of 40 km/h collide and rebound with the same velocity. What will be the impulse imparted to each ball due to other ball?

Question

Two billiard balls each of mass 50 g moving in opposite directions with a speed of 40 km/h collide and rebound with the same velocity. What will be the impulse imparted to each ball due to other ball? (A) 2.22 kg m/s (B) 1.11 kg m/s (C) 3.33 kg m/s (D) 4 kg m/s

Tardigrade Admin · Accepted Answer

Impulse imparted on billiard ball is equal to the change in momentum of the balls.

I = m v - m u = m (v - u)

(u = - v

rebound with same velocity)

I = m (v - (- v))

I = 2 m v = 2 \times 50 \times 1 0^{- 3} \times 40 \times \frac{5}{18}

I = 1 0^{- 1} \times 2.22 \times 5

I = 1.11 k g m / s

Q. Two billiard balls each of mass 50 g moving in opposite directions with a speed of 40 km/h collide and rebound with the same velocity. What will be the impulse imparted to each ball due to other ball?

2.22 kg m/s

1.11 kg m/s

3.33 kg m/s

4 kg m/s

Impulse imparted on billiard ball is equal to the change in momentum of the balls. I=mv−mu=m(v−u) (u=−v rebound with same velocity) I=m(v−(−v)) I=2mv=2×50×10−3×40×185​ I=10−1×2.22×5 I=1.11kgm/s