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  4. Two billiard balls each of mass 50 g moving in opposite directions with a speed of 40 km/h collide and rebound with the same velocity. What will be the impulse imparted to each ball due to other ball?

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Q. Two billiard balls each of mass 50 g moving in opposite directions with a speed of 40 km/h collide and rebound with the same velocity. What will be the impulse imparted to each ball due to other ball?

Laws of Motion

Solution:

Impulse imparted on billiard ball is equal to the change in momentum of the balls.
$I=m v-m u=m(v-u)$
$(u=-v$ rebound with same velocity)
$I=m(v-(-v)) $
$I=2 m v=2 \times 50 \times 10^{-3} \times 40 \times \frac{5}{18} $
$I=10^{-1} \times 2.22 \times 5$
$I=1.11 kg m / s$