Two batteries, one of E.M.F. 18 V and internal resistance 2 Ω and other of E.M.F. 12 V and internal resistance 1 Ω , are connected as shown. The voltmeter V will record a reading of

Question

<img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-cgvl6emo4oxivvof.jpg" /> Two batteries, one of E.M.F. 18 V and internal resistance 2 Ω and other of E.M.F. 12 V and internal resistance 1 Ω , are connected as shown. The voltmeter V will record a reading of (A) 30V (B) 18V (C) 15V (D) 14 V

Tardigrade Admin · Accepted Answer

Since the cells are in parallel, textV=(( textE1/ textr1) + ( textE2/ textr2)/(1) textr1 + (1) textr2=((18/2) + (12/1)/(1)2 + (1)1=(21/ text1.5)=14V

Q.
Two batteries, one of E.M.F. $18 V$ and internal resistance $2 Ω$ and other of E.M.F. $12 V$ and internal resistance $1 Ω$ , are connected as shown. The voltmeter $V$ will record a reading of

$30 V$

$18 V$

$15 V$

$14 V$

Since the cells are in parallel, $V = \frac{\frac{E _{1}}{r _{1}} + \frac{E _{2}}{r _{2}}}{\frac{1}{r _{1}} + \frac{1}{r _{2}}} = \frac{\frac{18}{2} + \frac{12}{1}}{\frac{1}{2} + \frac{1}{1}} = \frac{21}{1.5} = 14 V$

Q. Two batteries, one of E.M.F. 18V and internal resistance 2Ω and other of E.M.F. 12V and internal resistance 1Ω , are connected as shown. The voltmeter V will record a reading of

30V

18V

15V

14V