Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was

Question

Tuning fork F1 has a frequency of 256 Hz and it is observed to produce 6 beats/second with another tuning fork F2. When F2 is loaded with wax, it still produces 6 beats/second with F1. The frequency of F2 before loading was (A) 253 Hz (B) 262 Hz (C) 250 Hz (D) 259 Hz

Tardigrade Admin · Accepted Answer

nA= Known frequency =341 Hz , nB= ? x=6 bps, which is decreasing (i.e., x downarrow) after loading (from 6 to 1 bps) x=6 bps, which remains the same after loading. Unknown tuning fork F2 is loaded so nB downarrow Hence nA-nB downarrow=x ldots (i) Wrong nB downarrow-nA=x ldots (ii) Correct ⇒ nB=nA+x=256+6=262 Hz

Q. Tuning fork F1​ has a frequency of 256Hz and it is observed to produce 6 beats/second with another tuning fork F2​. When F2​ is loaded with wax, it still produces 6 beats/second with F1​. The frequency of F2​ before loading was

253 Hz

262 Hz

250 Hz

259 Hz

Q. Tuning fork $F_{1}$ has a frequency of $256 Hz$ and it is observed to produce 6 beats/second with another tuning fork $F_{2}$ . When $F_{2}$ is loaded with wax, it still produces 6 beats/second with $F_{1}$ . The frequency of $F_{2}$ before loading was